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SSC CGL 2018 Tier 2 Survey Analysis

Β· 3 min read Β· by QMaths

SSC CGL 2018 Tier 2 Survey Analysis

Normalization Formula

Where:

𝑴 π’Šπ’‹ = Normalized marks of jth candidate in the ith shift.

π‘΄π’•π’ˆ = is the average marks of the top 0.1% of the candidates considering all shifts (8,35).

π‘΄π’ˆ 𝒒 = is the sum of mean and standard deviation marks of the candidates in the examination considering all shifts.

π‘΄π’•π’Š= is the average marks of the top 0.1% of the candidates in the ith shift (RTI Table).

π‘΄π’Š 𝒒= is the sum of mean marks and standard deviation of the ith shift.

π‘΄π’Šπ’‹= is the actual marks obtained by the jth candidate in ith shift.

π‘΄π’ˆπ’Ž 𝒒 = is the sum of mean marks of candidates in the shift having maximum mean and standard deviation of marks of candidates in the examination considering all shifts.

Calculation of marks will be done up to 5 decimal places

RTI Regarding No of candidates Appeared on SSC CGL 2018 Tier 1 & tier 2

Normalization in SSC CGL 2018 Tier 1

Normalization in SSC CGL 2018 Tier 2

** Marks Range and Cumulative Data (Tier 2)

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